Show function source in repl?

[lc9er]

Is there a way to show a function's source code in the repl? Was goofing around directly in the repl (instead of sending from a file) and wanted to double check something. I tried using (describe myFunction), to see it returns "". I know this works in Common Lisp, and it looks like it works in Janet for variables, but is there a way to see a function's source in the repl?

[sogaiu]

AFAIK, there isn't a way to do this currently.

[lc9er]

Fair enough. Kind of what I figured. Thanks for the verification.

[sogaiu]

I looked into this a bit more and discovered that starting janet with -d [1] leads to something like the source being retained:

$ janet -d
Janet 1.38.0-b27c830d linux/x64/gcc - '(doc)' for help
repl:1:> (defn a [x] (+ x 1))
<function a>
repl:2:> (get (dyn 'a) :source-form)
(defn a [x] (+ x 1))

I think what is accessible via :source-form is not a string though so no formatting info is available IIUC.

---

[1] See this line.

[lc9er]

Very cool! Thanks for sharing this. Even without formatting, this is very useful.

…

On Fri, May 2, 2025 at 5:05 AM sogaiu ***@***.***> wrote: I looked into this a bit more and discovered that starting janet with -d leads to something like the source being retained: $ janet -d Janet 1.38.0-b27c830d linux/x64/gcc - '(doc)' for help repl:1:> (defn a [x] (+ x 1)) <function a> repl:2:> (get (dyn 'a) :source-form) (defn a [x] (+ x 1)) I think what is accessible via :source-form is not a string though so no formatting info is available IIUC. — Reply to this email directly, view it on <#1592 (reply in thread)>, or unsubscribe <https://.com/notifications/unsubscribe-auth/AE2BFH6OVRKW5QCUQY3TJNT24MYNTAVCNFSM6AAAAAB356NCA6VHI2DSMVQWIX3LMV43URDJONRXK43TNFXW4Q3PNVWWK3TUHMYTGMBRGE4TQMQ> . You are receiving this because you authored the thread.Message ID: ***@***.***>